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Given $A = \begin{pmatrix} 2 & 1 \\ 0 & 3 \end{pmatrix}$ and $B = \begin{pmatrix} 1 & 4 \\ -2 & 5 \end{pmatrix}$, find $2A - B$.
Solution
Given $A = \begin{pmatrix} 1 & 2 \\ 3 & 4 \end{pmatrix}$ and $B = \begin{pmatrix} 5 & 6 \\ 7 & 8 \end{pmatrix}$, find $AB$.
Solution
Multiply the $1 \times 3$ row vector $\begin{pmatrix} 1 & 2 & 3 \end{pmatrix}$ by the $3 \times 1$ column vector $\begin{pmatrix} 2 \\ 0 \\ 4 \end{pmatrix}$.
Solution
Find the inverse of $A = \begin{pmatrix} 2 & 1 \\ 5 & 3 \end{pmatrix}$, and check your answer.
Solution
$$A\mathbf{x} = \mathbf{b} \;\Rightarrow\; \mathbf{x} = A^{-1}\mathbf{b}$$
Solve the system $2x + y = 8$ and $5x + 3y = 21$ using matrices.
Solution
| Later topic | What the matrix does |
|---|---|
| AHL 3.9 Transformations | Rotates, reflects, or stretches shapes |
| AHL 3.15 Adjacency matrices | Records connections; powers count walks |
| AHL 4.19 Markov chains | Steps a probability model forward in time |
| AHL 1.15 Eigenvalues | Uses the identity and determinant you met here |